X^2=196x=

Solution for X^2=196x= equation:

X^2=196X=

We move all terms to the left:

X^2-(196X)=0

a = 1; b = -196; c = 0;
Δ = b2-4ac
Δ = -1962-4·1·0
Δ = 38416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{38416}=196$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-196)-196}{2*1}=\frac{0}{2}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-196)+196}{2*1}=\frac{392}{2}
=196
$